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How to make random positions in Equatorial coordinate system?
If I divide Dec between -90 and 90 evenly, the space distribution is not random.
Well, your problem is that you have a sphere. To compensate for the polar declination skew, you just calculate $$sin^{-1}(mathtt{rand})$$ Where $mathtt{rand}$ is a number in an evenly divided -1 to 1 range. Alternatively, you can use another trigonometric function based on what you have available, but you get the idea.
RA can obviously be divided evenly.
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